b_4 = \frac{46}{81} - \frac{1}{3} \cdot \frac{97336}{531441} = \frac{46}{81} - \frac{97336}{1594323}
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- $ b_3 = M(b_2) = \frac{2}{3} - \frac{(\frac{2}{3})^3}{3} = \frac{2}{3} - \frac{8}{81} = \frac{54 - 8}{81} = \frac{46}{81} $
- $ b_4 = M(b_3) = \frac{46}{81} - \frac{(\frac{46}{81})^3}{3} $
- First, compute $ \left( \frac{46}{81} \right)^3 = \frac{97336}{531441} $, so
- Convert $ \frac{46}{81} $ to denominator $ 1594323 $:
- \frac{46}{81} = \frac{46 \cdot 19683}{1594323} = \frac{904518}{1594323}
- b_4 = \frac{904518 - 97336}{1594323} = \frac{807182}{1594323}
