So $a = -2$, $b = 4$
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- At $x = \omega$:
- $(-\omega) + 3(-1) + (-2)(\omega - 1) + \omega + 5 = -\omega - 3 -2\omega + 2 + \omega + 5$
- Combine: $(-\omega -2\omega + \omega) = -2\omega$, $(-3 + 2 + 5) = 4$ â $-2\omega + 4$
- But let's verify with another point or use polynomial identity.
- Let $D(x) = x^4 + 3x^3 - 2x^2 + x + 5$, $D(x) = (x^2 - x + 1)(x^2 + ax + b) + (-2x + 4)$
- Compute RHS:
